E Exercises

Andromaque Jean-Louis problem 9.54 Faced with arise fax costs, a homogenous issued a guideline that transmissions of 10 pages or more should be sent by 2-day ring armour instead. Exceptions are allowed, but they flock the average to be 10 or below. The firm examined 35 randomly chosen fax transmissions during the next year, yielding a sample tight of 14.44 with a standard deviation of 4.45 pages. (a) At the .01 train of significance, is the true plastered great than 10? (b) exercise Excel to chance upon the right-tail p-value. a) At the .01 level of significance, is the true hatch greater than 10? The searing value for one-tail essay with of import is equal to 1 % which df=34 which is equal to 2.32634 The canvas statistic is z(14.44) which translates to (14.44-10)/[4.45/? (35)] equals 5.9028 Ha: ? > 10 Ho: ? = 10 The test statistics is in the rejected interval of Ho. in that respect is enough evidence back up the claim the true mean is greater than 10. b) Use Excel to find the right-tail p-value? p-value = P(5.9028 < t < 10) = 0.00000057579... = 1 NORMSDIST(5.9027) hassle 9.56 A take was flipped 60 times and came up heads 38 times. (a) At the .

10 level of significance, is the expunge biased toward heads? take your final stage rule and calculations. (b) Calculate a p-value and interpret it. a) At the .10 level of significance, is the gold biased toward heads? Show your decision rule and calculations. Ha: p> 0.5 Ho: p< 0.5 ? = np = (60)(0.5) = 30 ? = ?npq = ?(0.5)(0.5)(60) = 3.8730 (38 - 30) / 3.8730 = 2.0656 As the test statistic is greater than critical value, rid of Ho The test reflects that the coin is biased toward heads. b) Calculate a p-value and interpret it. p(z > 2.0656) = 0.0194 The Null possibleness is rejected and the claim is supported.If you regard to get a replete(p) essay, order it on our website: Orderessay

If you want to get a full information about our service, visit our page: How it works.