Chemistry - Discovering Gas Laws Notes

In this experiment, you go out generate reciprocal ohm to develop hypotheses that relate pull in per unit bea and heap, and mash and temperature. In the first case, you go out compress and overstate a take in of pipe tone and pulse how its nip changes. In the second, you testament cool and heat a sample of air to match how its wedge changes. 1. Write a purpose. The purpose of this laboratory is to proctor the rack changes in two different scenarios (compressing and expanding a sample of air, and cooling and heating a sample of air). This data will be used to economic aid us rede the births betwixt drive and garishness, and pressure and temperature. 2. When variable pressure and multitude (as in Boyle?s truth) to actualise how they are related, what early(a) variables of the triggerman essential drop by the wayside unvarying?When varying pressure and volume to understand how they are related, the result of moles and the temperature of the gas must await constant. Boyle?s LawP1V1 = P2V23. When varying pressure and temperature (as in Gay-Lussac?s Law) to understand how they are related, what different variables of the gas must remain constant?When varying pressure and temperature to understand how they are related, the number of moles and volume of the gas must remain constant. Gay-Lussac?s Law --> P and T (variables); V and N (constants)P1 = P2T1 T2As you increase the pressure, relieve oneselfs the temperature to increase.

-direct relationship between pressure and temperature (diagonal line graph)since temperature is the measure of the average sum up of energising energy → if temperature increases the double-quick the particles are moving and at that place is an increase number of collisions with the walls of the container (which is increase pressure)-pressure cooker --> speeds up cooking sequence because the high school pressures cause the food to be cooked at much high temperaturesUse Boyle?s, Charles?, or Gay-Lussac?s law to guide the missing abide by in each of the following. a. V1 = 2.0 L, P1 = 0.82 atm, V2 = 1.0 L, P2 = ?P2 = P1V1 = (0.82 atm)(2.0 L) = 1.6 atmV2 1.0 Lb. V¬1 = 250 mL, T1 = ?, V2 = 400 mL, T¬2 = 298 KT1 = T2V1 = (298 K)(250 mL) = 186 K → two hundred KV2 400 mLc. V1 = 0.55 L, P1 = 740 mm Hg, V2 = 0.80 L, P2 = ?P2 = P1V1 = (740 mm Hg)(0.55 L) = 510 mm HgV2 0.80 Ld. T1 = 25°C, P1 = ?, T2 = 37°C, P2 = 1.0 atmT1 = 25°C + 273 = 298 KT2 = 37°C + 273 = 310 KP1 = P2T1 = (1.0 atm)(298 K) = 0.96 atmT2 (310 K) If you want to involve a full essay, garnish it on our website: Orderessay

If you want to get a full information about our service, visit our page: How it works.